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2013
DOI: 10.4169/college.math.j.44.2.089
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Who Solved the Bernoulli Differential Equation and How Did They Do It?

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Cited by 11 publications
(5 citation statements)
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“…Proof Based on Bernoulli's equation in Reference 38, from (4), one gets truex˙k()t=()txk()tprefix−()c1j=1M.15emakj+γkxk2()t,$$ {\dot{x}}_k(t)=\hslash (t){x}_k(t)-\left({c}_1\sum \limits_{j=1}^M\kern.15em {a}_{kj}+{\gamma}_k\right){x}_k^2(t), $$ where ()t=c1j=1M.15emakjxj()t+c1j=1M.15emlkjxϑj+γkxϑj$$ \hslash (t)={c}_1\sum \limits_{j=1}^M\kern.15em {a}_{kj}{x}_j(t)+{c}_1\sum \limits_{j=1}^M\kern.15em {l}_{kj}{x}_{\vartheta_j}+{\gamma}_k{x}_{\vartheta_j} $$. Let zk()t=xkprefix−1()t$$ {z}_k(t)={x}_k^{-1}(t) $$.…”
Section: Resultsmentioning
confidence: 99%
“…Proof Based on Bernoulli's equation in Reference 38, from (4), one gets truex˙k()t=()txk()tprefix−()c1j=1M.15emakj+γkxk2()t,$$ {\dot{x}}_k(t)=\hslash (t){x}_k(t)-\left({c}_1\sum \limits_{j=1}^M\kern.15em {a}_{kj}+{\gamma}_k\right){x}_k^2(t), $$ where ()t=c1j=1M.15emakjxj()t+c1j=1M.15emlkjxϑj+γkxϑj$$ \hslash (t)={c}_1\sum \limits_{j=1}^M\kern.15em {a}_{kj}{x}_j(t)+{c}_1\sum \limits_{j=1}^M\kern.15em {l}_{kj}{x}_{\vartheta_j}+{\gamma}_k{x}_{\vartheta_j} $$. Let zk()t=xkprefix−1()t$$ {z}_k(t)={x}_k^{-1}(t) $$.…”
Section: Resultsmentioning
confidence: 99%
“…The equation ( 65) is the well known Bernoulli equation (e.g. see [15]). Under assumptions of corollary 1 the model was originally considered in [8].…”
Section: Remark On Fractional Sir Modelsmentioning
confidence: 99%
“…Thus: In this study we introduced the q-analogue Bernoulli's equation. A free analogue of some nuclear algebras of operators acting on space of holomorphic functions on a free analogue complexification of real nuclear space can be studied and we expect to develop a new quantum white noise analogue of free-Bernoulli's equation (Rguigui, 2015;Parker, 2013;Rguigui, 2016ab;2018a-b;Altoum, 2018).…”
Section: S Equationmentioning
confidence: 99%