2020
DOI: 10.1016/j.topol.2020.107245
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Well-filterifications of topological spaces

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Cited by 17 publications
(21 citation statements)
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“…It is not difficult to check that the space X is a WD space but not a Rudin space. Therefore, Example 4.15 in [36] also gave a negative answer to another related question raised by Xu, Shen, Xi and Zhao in [51]: Is every well-filtered determined space a Rudin space?…”
Section: Rudin Sets and Well-filtered Determined Setsmentioning
confidence: 99%
See 1 more Smart Citation
“…It is not difficult to check that the space X is a WD space but not a Rudin space. Therefore, Example 4.15 in [36] also gave a negative answer to another related question raised by Xu, Shen, Xi and Zhao in [51]: Is every well-filtered determined space a Rudin space?…”
Section: Rudin Sets and Well-filtered Determined Setsmentioning
confidence: 99%
“…( [51]) For any T 0 space X, S c (X) ⊆ D c (X) ⊆ RD(X) ⊆ WD(X) ⊆ Irr c (X). In [36,Example 4.15], Liu, Li and Wu constructed a T 0 space X in which some well-filtered determined sets are not Rudin sets, and hence gave a negative answer to a queston posed by Xu and Zhao in [55]: Does RD(X) = WD(X) hold for every T 0 space X? It is not difficult to check that the space X is a WD space but not a Rudin space.…”
Section: Rudin Sets and Well-filtered Determined Setsmentioning
confidence: 99%
“…Lemma 2.16. [9] Let N = (N, τ cof ), where τ cof denotes the cofinite topology, and X n an irreducible T 0 space for every n ∈ N , such that there are at most finitely many X n 's that have a greatest element under the specialization order…”
Section: Definition 23 ([4]mentioning
confidence: 99%
“…In [9], Liu, Li and Wu give a counterexample to show that WD(X) may not agree with KF(X) for any T 0 space X, which solved the open problem proposed by Xu in [15]. Zhang and Li provided a direct characterization of the D-completion of a T 0 space using the tapered closed subsets ( [16]).…”
Section: Introductionmentioning
confidence: 99%
“…In [14,Example 4.15], a well-filtered space X but not a Rudin space was given. It is straightforward to check that X is not first-countable.…”
mentioning
confidence: 99%