1956
DOI: 10.1137/1101013
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Weak Convergence of Stochastic Processes Whose Trajectories Have No Discontinuities of the Second Kind and the “Heuristic” Approach to the Kolmogorov-Smirnov Tests

Abstract: In 1934 A. N. Kolmogorov proved the following Theorem. I/(t) is a separable (see [1]) stochastic process, (1) Ml(tl)-(t)i < clq-t,.I+, where p > O, r > 0 and C is a constant independent o/ t, then the trajectories o/ the process are continuous with probability 1% A generalization of this theorem is the following proposition which was suggested to the author by A. N. Kolmogorov" Theorem 1. I/ (t) is a separable stochastic process, 0 < _ 1, andand C is a constant independent o/t, then the trajectories o/ the pro… Show more

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Cited by 80 publications
(46 citation statements)
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“…= [a, b] a non-trivial compact subinterval of I and choose an integer 0 such that 2-(~+D/~ By the proof of Theorem 5.1 of [9] and the hypothesis (ii)(a), for all t ~ K, So, hypothesis (ii)(b) together with Lemma 2.2 applied with A 1 = AZ = A3 = At and m = mK yield a constant C1 such that for all (t, h) E K x R+ such that t + h E K Then, the Kolmogorov-Tchentov Theorem [16] yields a continuous modification t )2014~ Yt of t Yt.…”
Section: Proof Of Theoremmentioning
confidence: 94%
“…= [a, b] a non-trivial compact subinterval of I and choose an integer 0 such that 2-(~+D/~ By the proof of Theorem 5.1 of [9] and the hypothesis (ii)(a), for all t ~ K, So, hypothesis (ii)(b) together with Lemma 2.2 applied with A 1 = AZ = A3 = At and m = mK yield a constant C1 such that for all (t, h) E K x R+ such that t + h E K Then, the Kolmogorov-Tchentov Theorem [16] yields a continuous modification t )2014~ Yt of t Yt.…”
Section: Proof Of Theoremmentioning
confidence: 94%
“…Now observe that, when taking the Q N -expectation, the contribution from the summand for j = 1 can be dropped since it has vanishing F N n -conditional expectation due to the martingale property of M N under Q N . From (3.12) Let us next focus on Law(M N | Q N ) N =1,2,... for which we will verify Kolmogorov's tightness criterion (see [5]) on C[0, 1]. To this end, recall that M N n+j /M N n+j−1 − 1 = O(1/ √ N ) and so the quadratic variation of M N satisfies…”
Section: Technical Preparationsmentioning
confidence: 95%
“…Not only is the solution to (1.4) continuous, but ( 1 2 − ε)-Hölder continuous for any ε ∈ (0, 1 2 ) as a consequence of the Kolmogorov-Centsov theorem [16]. Existence and precise meaning of G α Y is delicate, and is treated below.…”
Section: Weak Convergence Of Rough Volatility Modelsmentioning
confidence: 99%