“…If k = C, then complex conjugation induces the Hodge symmetry h 1,0 = h 0,1 . However, in positive characteristic, this Hodge symmetry may fail in general (see [Se58] and [Li08] for examples), and thus, we have to compute h 1,0 (X) another way: using the isomorphism E ∨ ∼ = E ⊗det(E), which holds for locally free sheaves of rank 2 (see [Har77, Exercise II.5.16], for example), we find T X ∼ = Ω 1 X/k for a K3 surface, and thus…”