2011
DOI: 10.1090/s0002-9939-2011-11483-7
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Uniform equicontinuity of sequences of measurable operators and non-commutative ergodic theorems

Abstract: The notion of uniform equicontinuity in measure at zero for sequences of additive maps from a normed space into the space of measurable operators associated with a semifinite von Neumann algebra is discussed. It is shown that uniform equicontinuity in measure at zero on a dense subset implies the uniform equicontinuity in measure at zero on the entire space, which is then applied to derive some non-commutative ergodic theorems.

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Cited by 22 publications
(28 citation statements)
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“…. At this moment we apply inequality (6) to the sequence {a k } ⊂ M yielding in view of (1) and (2) that sup λ∈C1 a n (x, λ)p Thus, we conclude that (7) lim n→∞ sup λ∈C1 a n (x, λ)p ∞ = 0, whence x ∈ W W .…”
Section: Proof Of the Main Resultsmentioning
confidence: 96%
See 1 more Smart Citation
“…. At this moment we apply inequality (6) to the sequence {a k } ⊂ M yielding in view of (1) and (2) that sup λ∈C1 a n (x, λ)p Thus, we conclude that (7) lim n→∞ sup λ∈C1 a n (x, λ)p ∞ = 0, whence x ∈ W W .…”
Section: Proof Of the Main Resultsmentioning
confidence: 96%
“…Therefore α(a n (x)) → α(x) in L 2 , so α(x) =x, and the ergodicity of α implies thatx = c(x) · I. Then, since τ is also continuous in L 2 , we have τ (a n (x)) → τ (x) = c(x), hence c(x) = τ (x) because τ (a n (x)) = τ (x) for each n. It is known ( [4], [6]) that a n (x) →x ∈ L 2 a.u., which implies that a n (x) →x in measure. Since · 2 −convergence entails convergence in measure, we conclude thatx =x = τ (x) · I.…”
Section: Proof Of the Main Resultsmentioning
confidence: 99%
“…(respectively, a.u.). Later, in [10] (see also [2]), it was shown that this result can be obtained directly from Yeadon's maximal inequality for L 1 (M, τ ) established in [21]. In particular, it was shown that a.u.…”
Section: Introductionmentioning
confidence: 89%
“…The main finding of the article is Lemma 3.2 where the matrix {e k,n } of projections in M is constructed. Also, the notion of (bilaterally) uniform equicontinuity in measure at zero of a family of maps from a normed space into the space of τ −measurable operators (see [10]) plays an important role.…”
Section: Introductionmentioning
confidence: 99%
“…The asymmetric result can be seen as a generalization of [31] (see also [19,18]). We will need the following proposition, whose proof is immediate (and thus we omit it).…”
Section: The Jessen-marcinkiewicz-zygmund Inequalitymentioning
confidence: 98%