2003
DOI: 10.1021/om030447r
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Unexpected Coupling of Cp and Two RNC Ligands at a {Mo2(μ-SMe)3} Nucleus

Abstract: Reaction of the bis-isonitrile complex [Mo2Cp2(μ-SMe)3(t-BuNC)2](BF4) (1) with n-BuLi (in hexane) produced the dealkylated derivative [Mo2Cp2(μ-SMe)3(t-BuNC)(CN)] (2) in quantitative yield. However, upon treatment with either NaOH (suspension) or (Me4N)OH (in MeOH), 1 was converted into a mixture of 2 and the μ-alkylidyne species [Mo2Cp(μ-SMe)3{μ-(η5-C5H4)(t-BuN)CN(t-Bu)C}] (3), in which a deprotonated Cp and both isonitrile ligands of 1 are now linked by new carbon−carbon and carbon−nitrogen bonds.

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Cited by 28 publications
(48 citation statements)
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“…Although the neutral derivatives 5 and 6 were difficult to separate, 6 was obtained in pure form, as shown below. Compound 5 was identified by comparing the 1 H NMR spectrum of a solution of the two products 5 and 6 of Reaction (3) with that of a pure sample of 5 obtained by the method described in Section 2.2. …”
Section: -Momentioning
confidence: 99%
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“…Although the neutral derivatives 5 and 6 were difficult to separate, 6 was obtained in pure form, as shown below. Compound 5 was identified by comparing the 1 H NMR spectrum of a solution of the two products 5 and 6 of Reaction (3) with that of a pure sample of 5 obtained by the method described in Section 2.2. …”
Section: -Momentioning
confidence: 99%
“…When R is a good electron-donor, such as Bu t , no activation of the cyclopentadienyl carbon atoms occurs and thus no cyclopentadiene derivative is formed. However, when the anionic compound reacting with 1a is LiBu n , a dealkylation reaction, involving ejection of the Bu t group, is observed (Scheme 3) [3]; this requires that LiBu n should act as a base. On the other hand, when the anionic reagent is BH À 4 , hydride attack occurs at the isonitrile carbon in 1a (L = Bu t NC), affording the l-formimidoyl derivative 4.…”
Section: Factors Influencing the Regiochemical Control In The Reactiomentioning
confidence: 99%
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