Catalytic tests for ethanol conversion were performed on vanadium and molybdenum oxides with different oxidation states. We found for the first time that equivalent amounts of ethane and acetaldehyde were formed catalytically over V 2 O 3 and MoO 2 . No influence of the reaction temperature was observed on the selectivity to ethane and acetaldehyde in the range of 533-653 K over V 2 O 3 and MoO 2 . The reactions of methanol, 1-propanol, and 2-propanol also produced the corresponding alkanes and aldehydes in a 1:1 ratio. A reaction scheme for the formation of ethane and acetaldehyde from ethanol is proposed in which a hydrogen transfer reaction occurs between two ethanol molecules adsorbed on the adjacent metal cation-oxygen anion pair sites to form ethane, acetaldehyde, and water in one step.Vanadium and molybdenum oxide catalysts have attracted much attention because of their unique catalytic properties and commercial application in various chemical processes. These catalysts are known to be active as oxidation and acid catalysts in reactions such as the partial oxidation of alkanes [1] and dehydration of alcohols. [2] In reports on the reaction of alcohols over vanadium and molybdenum oxide catalysts, the catalytic reaction was performed in the presence of oxygen and aldehydes, and carboxylic acid and CO 2 were produced. However, we found that ethane was formed from ethanol conversion over vanadium and molybdenum oxides under N 2 . The formation of alkanes from the corresponding alcohols is not normally a feature of the dehydration and dehydrogenation of alcohols. There is no report that describes the formation of alkanes from alcohols over reduced vanadium or molybdenum oxides. However, several reports describe the formation of alkanes from the corresponding alcohols, which are summarized in Table 1.McMonagle and Moffat proposed that the formation of ethane from ethanol over 12 molybdophosphates proceeds through the secondary hydrogenation of ethylene formed by the dehydration of ethanol because the selectivity to ethane increased in the presence of H 2 and the selectivity to acetaldehyde was always higher than that of ethane. In this study, Mo 6+ in the catalyst was reduced to Mo 5+ during the reaction.The selectivities to ethane and acetaldehyde decreased and the selectivity to ethylene increased over the reduced catalyst because of the loss of active sites for the dehydrogenation of ethanol. [3] Other reports also show the relationship between the selectivities to alkanes and aldehydes and the catalytic oxidation states. Abu-Zied and El-Awad showed that the formation of ethane from ethanol over Cd-Cr-O catalysts proceeded through the hydrogenation of ethylene produced by the dehydration of ethanol. As the selectivity to ethane increased with an increase in the selectivity to acetaldehyde and Cr is known to form hydride species, CrÀH was proposed as the active species in the hydrogenation of alcohols over Cr. In this reaction, Cr was reduced from Cr 6+ to Cr 3+ during the catalysis because of the absence of ...