“…If I ∈ [1,2] is considered as a possible interval range, then d 2 F(x * , I)/dx 2 > 0, and x * = 0 is the optimal solution for the minimum F(x * , I). Thus, the minimum value of the NN objective function is F(x * , I) = [5,10], which, in this case, is a possible interval range, but not always. Specifically if I = 1 (crisp value), then F(x * , I) = 5.…”