An ordered hexagonal lattice structure with a lattice constant of about 7 nm was reconstituted from outer membrane protein 0 -8 and/or 0 -9 and lipopolysaccharide [H. Yamada and S. Mizushima, J . Bacteriol. 135, 1024Bacteriol. 135, -1031Bacteriol. 135, (1978l. Using this reconstitution system, the interaction between 0 -8 and lipopolysaccharide was studied and the following results were obtained.At least one lipopolysaccharide molecule per one 0 -8 trimer was required for the hexagonal lattice formation. The lattice constant of the hexagonal lattice formed under the conditions was about 6.5 nm. In the presence of a larger amount of lipopolysaccharide, the lattice constant increased to 7.5 nm, being almost the same as that observed in the dodecylsulfate-treated cell envelope.The lattice constant observed with the heptoseless lipopolysaccharide was also 6.5 nm when the lipopolysaccharide/O-8 ratio was low. Although the increase of the lattice constant was observed upon further addition of the lipopolysaccharide, it was appreciably smaller than that with the wildtype lipopolysaccharide.A hexagonal lattice was also formed when lipopolysaccharide was replaced by an equivalent amount of lipid A or even fatty acids. The lattice constant was the same as that with the wild-type lipopolysaccharide when the lipid/protein ratio was low. However, contrary to the case of lipopolysaccharide, the lattice constant remained almost unchanged even when a larger amount of either lipid A or fatty acid was added to the reconstitution system. A slight increase in the lattice constant was observed only when an extremely large amount of lipid A was added to the reconstitution system.These results suggest that (1) both the lipid A moiety and the polysaccharide moiety of lipopolysaccharide participate in the interaction with the 0 -8 trimer, (2) in the lipid A moiety the fatty acid region primarily participates in the hexagonal arrangement of the 0 -8 trimer and the minimum requirement of lipopolysaccharide for the lattice formation is most probably one lipopolysaccharide molecule per 0 -8 trimer and (3) the polysaccharide moiety, probably both the 3-deoxy-~-mannooctulosonate region and the distal end region including heptose, are involved in an interaction of lipopolysaccharide with the 0 -8 trimer to give a proper lattice conformation.In a previous paper [l], we reported the following results for Escherichia coli K12: (a) an ordered hexagonal lattice structure with a lattice constant of about 7 nm was reconstituted on the entire surface of the lipoprotein-bearing peptidoglycan from outer membrane protein 0 -8 and lipopolysaccharide; (b) the lattice structure resembled that observed in the cell envelopes which had been treated with sodium dodecylsulfate; (c) in the absence of the lipoprotein-bearing peptidoglycan or in the presence of the peptidoglycan lacking the bound form of the lipoprotein, 0 -8 and/or 0 -9 and lipopolysaccharide assembled into vesicles with an ordered hexagonal lattice structure, the lattice constant of which was ...