Lecture Notes in Mathematics
DOI: 10.1007/bfb0065204
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Two-bridge knots have residually finite groups

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Cited by 2 publications
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“…Proof. From (19) we deduce h 2n (ω) 2 − 1 − 3n = ng n (ω) −2 A with A = −2(ω + 4) + 3(4 − g n (ω) 2 ). By Lemma 5.10 we have v(g n (ω)) = 0, so v(h 2n (ω) 2 − 1 − 3n) = v(n) + v(A).…”
Section: Smoothness and Irreducibility Of The Character Varietiesmentioning
confidence: 88%
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“…Proof. From (19) we deduce h 2n (ω) 2 − 1 − 3n = ng n (ω) −2 A with A = −2(ω + 4) + 3(4 − g n (ω) 2 ). By Lemma 5.10 we have v(g n (ω)) = 0, so v(h 2n (ω) 2 − 1 − 3n) = v(n) + v(A).…”
Section: Smoothness and Irreducibility Of The Character Varietiesmentioning
confidence: 88%
“…This presentation follows from the canonical Schubert normal form [30] of the two-bridge diagram of K(p, q) (see [25,Prop. 1], [20, (2.1)], [19,Prop. 1]).…”
Section: 2mentioning
confidence: 99%
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