2009
DOI: 10.1093/imrn/rnp070
|View full text |Cite
|
Sign up to set email alerts
|

Two Applications of Twisted Floer Homology

Abstract: Given an irreducible closed 3-manifold Y , we show that its twisted Heegaard Floer homology determines whether Y is a torus bundle over the circle. Another result we will prove is, if K is a genus 1 null-homologous knot in an L-space, and the 0-surgery on K is fibered, then K itself is fibered. These two results are the missing cases of earlier results due to the second author.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

0
19
0

Year Published

2009
2009
2024
2024

Publication Types

Select...
8

Relationship

0
8

Authors

Journals

citations
Cited by 16 publications
(22 citation statements)
references
References 20 publications
0
19
0
Order By: Relevance
“…In addition to the Thurston norm of a homology class, α ∈ H 2 (Y, ∂Y ), the Ozsváth-Szabó invariants answer the subtler question of when a knot complement or closed three-manifold fibers over the circle with fiber an embedded surface, Σ, whose homology class equals α [8,20,21,1]. For knots, this again has a beautiful corollary, namely that knot Floer homology detects the trefoil and figure eight knots [8].…”
Section: Introductionmentioning
confidence: 98%
“…In addition to the Thurston norm of a homology class, α ∈ H 2 (Y, ∂Y ), the Ozsváth-Szabó invariants answer the subtler question of when a knot complement or closed three-manifold fibers over the circle with fiber an embedded surface, Σ, whose homology class equals α [8,20,21,1]. For knots, this again has a beautiful corollary, namely that knot Floer homology detects the trefoil and figure eight knots [8].…”
Section: Introductionmentioning
confidence: 98%
“…Moreover, using Heegaard Floer homology, we can show that if HF red (Y ) = 0 then K has Property G. (For Property G2, the proof can be found in [10,1]. The proof for Property G1 is similar.…”
Section: Introductionmentioning
confidence: 91%
“…This case is sufficient for our applications. For our purpose, we will strengthen the statement of Theorem 1.1 by introducing 1 We will not prove this fact here, since we do not need it in our paper. 2 For example, let M = S 1 × B, where B is an orientable surface with exactly two boundary components C + , C − .…”
Section: Sketch Of Gabai's Constructionmentioning
confidence: 98%