2003
DOI: 10.1016/s0021-8693(03)00467-8
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Twisted tensor product of multiplier Hopf (∗-)algebras

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Cited by 15 publications
(40 citation statements)
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“…To see that the expressions for S # ((a#b )(x#y)) and S # (x#y)S # (a#b ) are equal, we use that S A is a braided anti-homomorphism, in the sense of Lemma 2.6. To finish the proof, we observe that for all a, x in A and b , y in B, we have # (a#b )((x#y) ⊗ (1#1)) = (ι ⊗ T ⊗ ι)( (a)((b (1) x)⊗1) ⊗ b (2) y ⊗ b (3) ) in (A#B) ⊗ (A#B).…”
Section: Radford's Biproduct For Multiplier Hopf Algebrasmentioning
confidence: 94%
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“…To see that the expressions for S # ((a#b )(x#y)) and S # (x#y)S # (a#b ) are equal, we use that S A is a braided anti-homomorphism, in the sense of Lemma 2.6. To finish the proof, we observe that for all a, x in A and b , y in B, we have # (a#b )((x#y) ⊗ (1#1)) = (ι ⊗ T ⊗ ι)( (a)((b (1) x)⊗1) ⊗ b (2) y ⊗ b (3) ) in (A#B) ⊗ (A#B).…”
Section: Radford's Biproduct For Multiplier Hopf Algebrasmentioning
confidence: 94%
“…This investigation for multiplier Hopf algebras is already done in special cases. More precisely, in [3], we take T equal to the usual flip map and in [4], we take R equal to the usual flip map. For a ∈ A and b ∈ B, the coproduct # (a#b ) will be introduced (as usual) via two linear maps T # 1 and T # 2 on (A#B) ⊗ (A#B).…”
Section: The Simultaneous Twisting Of Multiplications and Comultiplicmentioning
confidence: 99%
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“…By [4,5], all of these modules are unital if and only if one of them is unital. This will be shown in Proposition 2.4.…”
Section: Let K(g) K[h] and K[g] K(h)mentioning
confidence: 99%