“…with one regular part of the propagator inserted between two singular diffusons, D s = (Dq 2 − iω) −1 . Indeed, in view of n α D reg n β = 1 2 T αβ , the latter contribution reduces to − 1 2 D s 2 T αβ , while the diagrams a, b and c yield 47) where ǫ αβ is the antisymmetric tensor, ǫ xx = ǫ yy = 0, ǫ xy = −ǫ yx = 1. It remains thus to calculate only the contribution of the diagrams d + e with three singular diffusons, 48) in agreement with 1,10,11 .…”