2013
DOI: 10.1002/atr.1245
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Trial and error method for optimal tradable credit schemes: The network case

Abstract: Recent studies on the new congestion reduction method-tradable credit scheme rely on the full information of speed-flow relationship, demand function, and generalized cost. As analytical travel demand, functions are difficult to establish in practice. This paper develops a trial and error method for selecting optimal credit schemes for general networks in the absence of demand functions. After each trial of tradable credit scheme, the credit charging scheme and total amount of credits to be distributed are upd… Show more

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Cited by 25 publications
(8 citation statements)
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“…Later, Wang et al (2013) further extended the trial-and-error procedure for implementation of tradable credit schemes in general networks. The procedure updates tradable credit schemes from observed link flows and credit prices, based on the successive average method.…”
Section: Implementation Issue Under Limited Informationmentioning
confidence: 99%
“…Later, Wang et al (2013) further extended the trial-and-error procedure for implementation of tradable credit schemes in general networks. The procedure updates tradable credit schemes from observed link flows and credit prices, based on the successive average method.…”
Section: Implementation Issue Under Limited Informationmentioning
confidence: 99%
“…In the context of TCS, Wang and Yang [40] proposed a trial-and-error implementation of the tradable credit schemes for a single road. Later, the authors extended it to a general network case [41]. Different from the two existing works, which focus on solving equilibrium travel demand and optimal credit charge pattern, respectively, we propose a trial-and-error method for solving the equilibrium credit price in this paper.…”
Section: Solution Algorithmmentioning
confidence: 99%
“…''u = 1-16'' is the O-D pair in the network (Figure 1). The standard US Highway Bureau impedance function is employed as the link impedance function, 18,36 namely t i (F i ) = t 0 i ½1 + 0:15(F i =c i ) 4 . The relevant parameters of each link are shown in Table 1.…”
Section: Case Studymentioning
confidence: 99%