1997
DOI: 10.1002/1521-3951(199710)203:2<363::aid-pssb363>3.0.co;2-w
|View full text |Cite
|
Sign up to set email alerts
|

Transmission through the Symmetrical Double Delta Barrier with a Rectangular Well in between

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
2
1

Citation Types

1
6
0

Year Published

2009
2009
2018
2018

Publication Types

Select...
3
1

Relationship

1
3

Authors

Journals

citations
Cited by 4 publications
(7 citation statements)
references
References 0 publications
1
6
0
Order By: Relevance
“…In the case of the transmissions through the biased double delta-barrier, there also exists some constructive interference between the waves just transmitting through the first delta-barrier and those being reflected off the second one. Unlike the transmissions through the unbiased double delta-barrier [9][10][11], the constructive interference in the biased double delta-barrier is not strong enough to cause the ideal transmission. Thus, the applied voltage reduces the constructive interference between the waves in the double delta-barrier.…”
Section: Attributes Of the Transmission Coefficientsupporting
confidence: 52%
See 4 more Smart Citations
“…In the case of the transmissions through the biased double delta-barrier, there also exists some constructive interference between the waves just transmitting through the first delta-barrier and those being reflected off the second one. Unlike the transmissions through the unbiased double delta-barrier [9][10][11], the constructive interference in the biased double delta-barrier is not strong enough to cause the ideal transmission. Thus, the applied voltage reduces the constructive interference between the waves in the double delta-barrier.…”
Section: Attributes Of the Transmission Coefficientsupporting
confidence: 52%
“…Further, δ(x) is the Dirac delta-function and g is its strength (a positive value of the strength corresponds to a barrier, while a negative value would correspond to a well), Θ(x) is the Heaviside step function (Θ(x) = 0, if x < 0; and Θ(x) = 1, if x > 0), e is the elementary charge, V is the voltage applied to the double delta-barrier, 2a is the width of the double delta-barrier. Evidently, the wave function ϕ(x) is to be sought in the form of plane waves moving from the left to the right and vice versa [5][6][7][8][9][10][11][12][13][14]. Thus,…”
Section: Solution Of the Schrödinger Equationmentioning
confidence: 57%
See 3 more Smart Citations