A sodium channel is composed of four similar domains, each containing a highly charged S4 helix that is driven outward (activates) in response to a depolarization. Functionally, the channel has two gates, called activation gate (a gate) and inactivation gate (I gate), both of which must be open for conduction to occur. The cytoplasmically located a gate opens after a depolarization has activated the S4s of (probably) all four domains. The I gate consists of a cytoplasmically located inactivation ''particle'' and a receptor for it in the channel. The receptor becomes available after some degree of S4 activation, and the particle diffuses in to inactivate the channel. (2,3). The apparent voltage sensitivity of inactivation comes from the fact that a receptor for an ''inactivation particle'' becomes available only when the activation gate is partially or fully activated (2-5). These ideas, which preceded cloning of the channel, were summarized in the following state diagram (4), with the states renamed here for clarity (Scheme 1). At the resting potential, the preferred state is aC 0 (gate a closed and fully deactivated). After depolarization, several sequential steps are required to move the activation gate from aC 0 through the partially activated states (aC 1-4 ) to aO (gate a open). Each of these steps is voltage-dependent and involves the movement of gating charge (I g ) through the membrane, as indicated by q 1-5 . Increasingly positive voltage alters the rate constants of these steps and drives the channels to the right in the diagram. In the single conducting state (aO), both a and I gates are open, and the channel is conducting.Inactivation from aO occurs mainly in the step aO Ͼ aOI, with rate constants and . is small compared with , with the result that most channels inactivate. and are unaffected by membrane voltage (V m ), so no gating current is generated by this step. On repolarization, the channels recover from inactivation in a few milliseconds and return to state aC 0 . If the channels were frozen in aOI, there could be no gating current at the instant of repolarization, because none of the steps that involve gating charge movement (aOI 3 aC 0 ) could occur: All gating charge would be temporarily immobilized. In fact, a third of the charge is not immobilized (q ni ), and its movement produces a fast tail of inward I g , which is associated with step aOI 3 aC 4 I (3). This step closes the a gate, whereas the I gate remains closed, and the channel subsequently can recover from inactivation without passing through the conducting state, aO (6, 7). Because is small, very few channels move from aOI to aO, and recovery from inactivation mainly follows the path aOI 3 aC 4 I 3 aC 4 33 aC 0 , thus bypassing aO. This is important functionally, because recovery occurs at negative voltage, where influx of Na ϩ through any conducting channels would be large and would have a strong depolarizing influence.As first shown by Bean (8), the channel can inactivate without fully opening, as definitively confirmed by Al...