2019
DOI: 10.48550/arxiv.1905.01177
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To square root the Lagrangian or not: an underlying geometrical analysis on classical and relativistic mechanical models

Abstract: The geodesic has a fundamental role in physics and in mathematics: roughly speaking, it represents the curve that minimizes the arc length between two points on a manifold. We analyze a basic but misinterpreted difference between the Lagrangian that gives the arc length of a curve and the one that describes the motion of a free particle in curved space. Although they provide the same formal equations of motion, they are not equivalent. We explore this difference from a geometrical point of view, where we obser… Show more

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Cited by 5 publications
(9 citation statements)
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“…The above equivalence of S 1 and S 2 could be demonstrated on a more complicated Lagrangian as a specific choice of parametrization such that g αβ (x) v α v β is constant [28]. Indeed, if one starts with the re-parametrization invariant Lagrangian L = qA α v α −m g αβ (x)v α v β and defines proper time gauge τ such that: dτ = g αβ dx α dx β ⇒ g αβ u α u β = 1, then one can effectively consider L = qA α u α − (m − χ) g αβ u α u β − χ as the model Lagrangian.…”
Section: B Equivalence Of Homogenous Lagrangiansmentioning
confidence: 95%
See 1 more Smart Citation
“…The above equivalence of S 1 and S 2 could be demonstrated on a more complicated Lagrangian as a specific choice of parametrization such that g αβ (x) v α v β is constant [28]. Indeed, if one starts with the re-parametrization invariant Lagrangian L = qA α v α −m g αβ (x)v α v β and defines proper time gauge τ such that: dτ = g αβ dx α dx β ⇒ g αβ u α u β = 1, then one can effectively consider L = qA α u α − (m − χ) g αβ u α u β − χ as the model Lagrangian.…”
Section: B Equivalence Of Homogenous Lagrangiansmentioning
confidence: 95%
“…Since now S ′ 2 is reparametrization invariant then one can choose a gauge parametrization such that e = 1 and thus arriving at S 2 but under proper-time parametrization λ = τ where g αβ u α u β = 1. Having to choose the gauge such that g αβ v α v β is constant guarantees the equivalence of L 1 and L 2 [28].…”
Section: A Relativistic Particle Lagrangianmentioning
confidence: 99%
“…3.74 it is used that the expression is a tensor density and contains the information on the local momentum p of the system, which allows it to be interpreted as the root of a Lagrangian density. This is again equivalent to the interpretation as Lagrangian density L if trajectories along constant flow velocity are considered (Rizzuti, Vasconcelos & Resende 2019).…”
Section: Equation Of Momentum Density and Interpretation As Lagrangia...mentioning
confidence: 99%
“…We point out that the action of the group of covariance acts in a slightly non-linear way upon the physical sector of the models. Standard examples of such models are the free relativistic particle [15] and the electrodynamics Lagrangian action [12].…”
Section: The 5-dimensional Lagrangian Modelmentioning
confidence: 99%
“…These quantities are not chosen randomly. We simply follow the same steps taken on the standard analysis of the free relativistic particle model [15], or, by the same token, the semiclassical spinning particle model [17], in order to remove the so discussed arbitrariness our model possesses. First of all, we point out that these quantities remain unaltered under the local symmetries,…”
Section: Physical Sectormentioning
confidence: 99%