Abstract:to this compound is again based largely on its NMR spectrum (see Figure), in which the signals for the ring-and bridge protons exhibit the expected large shifts to lower (0.4-1.7 7 ) and higher fields (10.3 and 11.8 T, J = 10 cps),respectively,reIative to the signals in the spectrum of (2). Compound (2) and the salt ( 3 ) must have the same carbon skeleton, for on catalytic hydrogenation both give the same saturated hydrocarbon C12H~2, which we consider to be bicyclo [5,4, Ildodecane. The N M R and ultraviol… Show more
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