1972
DOI: 10.1063/1.3253100
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Thermal Conductivity of the Elements

Abstract: This is the abridged version of a comprehensive volume on the thermal conductivity of the elements. It contains recommended reference values resulting from critical evaluation, analysis, and synthesis of all the available data. It also gives estimated values for those elements for which no thermal conductivity data are available. Thus, the work provides recommended or estimated thermal conductivity values for all the elements over the full temperature ranges where experimental data are available or reliable ex… Show more

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Cited by 770 publications
(500 citation statements)
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“…Considering the measured thermal conductivity is independent of thickness, these boundaries must consist of internal grain boundaries. The trend of the curve as well as the peak position are consistent with prior experimental and theoretical works [32,33]. The measured bulk thermal conductivity at room temperature is between 6.4 W/mK to 7.0 W/mK, in agreement with the accepted value of 6.8 W/mK [14].…”
supporting
confidence: 89%
“…Considering the measured thermal conductivity is independent of thickness, these boundaries must consist of internal grain boundaries. The trend of the curve as well as the peak position are consistent with prior experimental and theoretical works [32,33]. The measured bulk thermal conductivity at room temperature is between 6.4 W/mK to 7.0 W/mK, in agreement with the accepted value of 6.8 W/mK [14].…”
supporting
confidence: 89%
“…(3a) reduces to -, (4) while at high temperatures (T >) R), to a good approximation, it reduces to Pi ~ 101…”
Section: P(ct) -P 0 (C) + Pi(t) + A(ct)mentioning
confidence: 99%
“…For the problem discussed here, we can find that the thermal resistance by radiation Z rad = ∆ T /(P rad (T ) − P rad (T b ))= ∆ T /(Q abs I inc πR 2 ) ≈ 1.27 10 17 ∆ T (in Kelvin/Watt). It is worth to mention that regardless of the value of ∆ T (> 1 K), the value of Z rad is always much smaller than the thermal resistance by conduction inside the NP Z cond ≈ 1/(2 Îș Au R)= 6.3 10 4 Kelvin/Watt (Îș Au =317 W/(m.K) at T = 300 K [33]). This is perfectly consistent with the assumption that the temperature inside the NP is uniform.…”
Section: B Steady-state Temperature Of the Npmentioning
confidence: 99%