2005
DOI: 10.1090/s0002-9939-05-08093-7
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The weak dimensions of Gaussian rings

Abstract: Abstract. We provide necessary and sufficient conditions for a Gaussian ring R to be semihereditary, or more generally, of w.dimR ≤ 1. Investigating the weak global dimension of a Gaussian coherent ring R, we show that the only values w.dimR may take are 0, 1 and ∞; but that f P.dimR is always at most one. In particular, we conclude that a Gaussian coherent ring R is either Von Neumann regular, or semihereditary, or non-regular of w.dimR = ∞.

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Cited by 36 publications
(30 citation statements)
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“…If R is a Gaussian ring, then is w.dim R = 0; 1, or 1? This is the case for coherent Gaussian rings [67,Theorem 3.3] (and actually, more generally, for coherent Prüfer rings [14, Proposition 6.1]), arithmetical rings [97 and 14, remark in the last paragraph], and a particular case of Gaussian rings [14,Theorem 6.4]. [68,Corollary 6.7], in which case w.dim R = 0 or 1 ; and also holds for one example of a non coherent ring [68,Example 6.8].…”
Section: Problemmentioning
confidence: 85%
See 2 more Smart Citations
“…If R is a Gaussian ring, then is w.dim R = 0; 1, or 1? This is the case for coherent Gaussian rings [67,Theorem 3.3] (and actually, more generally, for coherent Prüfer rings [14, Proposition 6.1]), arithmetical rings [97 and 14, remark in the last paragraph], and a particular case of Gaussian rings [14,Theorem 6.4]. [68,Corollary 6.7], in which case w.dim R = 0 or 1 ; and also holds for one example of a non coherent ring [68,Example 6.8].…”
Section: Problemmentioning
confidence: 85%
“…Glaz [67] and Bazzoni & Glaz [14] consider, among other properties, the …nitistic and weak global dimensions of rings satisfying various Prüfer conditions.…”
Section: Open Problems Problemmentioning
confidence: 99%
See 1 more Smart Citation
“…We note that it follows from Osofsky [17] that arithmetical rings have weak global dimension at most one or ∞. In the same vein, the author of [7] is concerned with giving a homological characterization to Gaussian rings. She considers the question: For a Gaussian ring R, what possible values may w. gl.…”
Section: Introductionmentioning
confidence: 95%
“…From Bazzoni and Glaz [4, Theorem 3.12], we note that a Prüfer ring R satisfies one of the five conditions if and only if the total ring of quotients T ot(R) of R satisfies the same condition. See for instance [3,4,7,10,11,13,17,23,28].…”
Section: Introductionmentioning
confidence: 99%