2021
DOI: 10.21595/jve.2021.22162
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The vibration response of transformer windings under harmonic excitations and its applications

Abstract: The power transformer is a key device in the power grid systems. The mechanical degradation of windings represented by the clamping force looseness will cause the decline of the short circuit withstand ability, and cause further damages. This paper proposes a clamping force diagnosis method for operating windings based on the study of the vibration response. In the theory part, the influence of the load current on the natural frequency of windings is discussed, and the influence of the natural frequency change… Show more

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Cited by 2 publications
(2 citation statements)
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“…The current is i(t)=I10.25emcos0.25emωt $i(t)={I}_{1}\hspace*{.5em}\mathrm{cos}\hspace*{.5em}\omega t$ and the coil radius is r , so the winding length is denoted as L=2normalπr $L=2{\uppi }r$. Therefore, according to the Ampere force formula F=BσIL $F={\boldsymbol{B}}_{\boldsymbol{\sigma }}IL$ [25], the radial and axial electromagnetic forces Fx ${F}_{x}$, Fz ${F}_{z}$ can be calculated. {Fx=2normalπrBbold-italicσbold-italiczi(t)=normalπrkzI1Iσ10.25emcos(2ωt)Fz=2normalπrBbold-italicσbold-italicxi(t)=normalπrkxI1Iσ10.25emcos(2ωt) $\left\{\begin{array}{l}{F}_{x}=2{\uppi }r{\boldsymbol{B}}_{\boldsymbol{\sigma }\boldsymbol{z}}i(t)={\uppi }r{k}_{z}{I}_{1}{I}_{\sigma 1}\hspace*{.5em}\mathrm{cos}(2\omega t)\\ {F}_{z}=2{\uppi }r{\boldsymbol{B}}_{\boldsymbol{\sigma }\boldsymbol{x}}i(t)={\uppi }r{k}_{x}{I}_{1}{I}_{\sigma 1}\hspace*{.5em}\mathrm{cos}(2\omega t)\end{array}\right.$ …”
Section: Axial and Radial Vibration Mechanisms Of Windings Under Fund...mentioning
confidence: 99%
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“…The current is i(t)=I10.25emcos0.25emωt $i(t)={I}_{1}\hspace*{.5em}\mathrm{cos}\hspace*{.5em}\omega t$ and the coil radius is r , so the winding length is denoted as L=2normalπr $L=2{\uppi }r$. Therefore, according to the Ampere force formula F=BσIL $F={\boldsymbol{B}}_{\boldsymbol{\sigma }}IL$ [25], the radial and axial electromagnetic forces Fx ${F}_{x}$, Fz ${F}_{z}$ can be calculated. {Fx=2normalπrBbold-italicσbold-italiczi(t)=normalπrkzI1Iσ10.25emcos(2ωt)Fz=2normalπrBbold-italicσbold-italicxi(t)=normalπrkxI1Iσ10.25emcos(2ωt) $\left\{\begin{array}{l}{F}_{x}=2{\uppi }r{\boldsymbol{B}}_{\boldsymbol{\sigma }\boldsymbol{z}}i(t)={\uppi }r{k}_{z}{I}_{1}{I}_{\sigma 1}\hspace*{.5em}\mathrm{cos}(2\omega t)\\ {F}_{z}=2{\uppi }r{\boldsymbol{B}}_{\boldsymbol{\sigma }\boldsymbol{x}}i(t)={\uppi }r{k}_{x}{I}_{1}{I}_{\sigma 1}\hspace*{.5em}\mathrm{cos}(2\omega t)\end{array}\right.$ …”
Section: Axial and Radial Vibration Mechanisms Of Windings Under Fund...mentioning
confidence: 99%
“…The current is iðtÞ ¼ I 1 cos ωt and the coil radius is r, so the winding length is denoted as L ¼ 2πr. Therefore, according to the Ampere force formula F ¼ B σ IL [25], the radial and axial electromagnetic forces F x , F z can be calculated.…”
Section: Winding Vibration Under Fundamental Currentmentioning
confidence: 99%