1981
DOI: 10.2307/1971376
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The Trace Formula in Invariant Form

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Cited by 135 publications
(151 citation statements)
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“…In order to solve this problem, we give a different argument, which works for all T . The resulting geometric side of the trace formula depends polynomially on T (with a slight modification in case of positive characteristic), as already proved in [3] in the sufficiently regular range. The previous lack of knowledge that the explicit expression is convergent for all T was the source of certain complications in [4], which may now be avoided, at least for compactly supported f .…”
Section: Introductionmentioning
confidence: 59%
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“…In order to solve this problem, we give a different argument, which works for all T . The resulting geometric side of the trace formula depends polynomially on T (with a slight modification in case of positive characteristic), as already proved in [3] in the sufficiently regular range. The previous lack of knowledge that the explicit expression is convergent for all T was the source of certain complications in [4], which may now be avoided, at least for compactly supported f .…”
Section: Introductionmentioning
confidence: 59%
“…Of course, it has to be shown that all sums and integrals occurring here are absolutely convergent. We are going to prove this when f is a suitable extension of a function in a certain Schwartz space C p (G(F S ) 1 ), which has been introduced in the case p = 2 in [3], p. 28, and is some kind of tensor product of the spaces introduced by Harish-Chandra. Namely, let Ξ v and σ v be the functions on G(F v ) used in [11] and [13] in the definition of C(G(F v )) (cf.…”
Section: The Resultsmentioning
confidence: 99%
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“…It has been shown ( [3], Lemma 8.1) that the integral converges and defines a tempered distribution J M (m) on G, i.e., a continuous linear functional on C(G). Note that v G is constant equal to 1, so that J G (g) is the ordinary (unweighted) orbital integral.…”
Section: Definitionmentioning
confidence: 99%
“…These are the main terms in the invariant trace formula [7]. There are two choices which are reciprocal in a certain sense ( [3], p. 7/8, [10], §3). It is analytically easier to modify the weighted orbital integrals.…”
Section: Invariant Distributionsmentioning
confidence: 99%