2014
DOI: 10.1515/advgeom-2014-0013
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The total Betti number of the intersection of three real quadrics

Abstract: The classical Barvinok bound for the sum of the Betti numbers of the intersection X of three quadrics in RP n says that there exists a natural number a such that b(X) ≤ n 3a . We improve this bound proving the inequality b(X) ≤ n(n + 1). Moreover we show that this bound is asymptotically sharp as n goes to infinity.

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Cited by 6 publications
(9 citation statements)
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“…i − (ωq − ǫp) = i + (ǫp − ωq). In particular the Betti numbers of Ω j+1 and of its perturbation Ω n−j (ǫ) are the same, as proved in the following lemma from [16].…”
Section: Transversality Argumentssupporting
confidence: 52%
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“…i − (ωq − ǫp) = i + (ǫp − ωq). In particular the Betti numbers of Ω j+1 and of its perturbation Ω n−j (ǫ) are the same, as proved in the following lemma from [16].…”
Section: Transversality Argumentssupporting
confidence: 52%
“…Recall that equation ( 19) was for a complete intersection of multidegree (2, δ) in CP 3 ; specifying it to this case δ = n + 1 we get b(C) ≤ 2n 2 + O(n), which plugged into the previous inequality gives: b(X) ≤ n 2 + O(n). (indeed Theorem 1 of [16] gives the refined bound b(X) ≤ n 2 + n). We notice now that in this case: B(3, n) = n 2 + O(n).…”
Section: Examplesmentioning
confidence: 98%
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“…Using the same technique, it is possible to prove that if X is the intersection of three real quadrics in RP n , then b(X) ≤ n(n + 1). The interested reader is referred to [16].…”
Section: B(x) ≤ 2nmentioning
confidence: 99%