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2002
DOI: 10.1016/s0012-365x(00)00454-4
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The three-way intersection problem for latin squares

Abstract: For µ given latin squares of order n, they have k intersection when they have k identical cells and n 2 − k cells with mutually different entries. For each n ≥ 1 the set of integers k such that there exist µ latin squares of order n with k intersection is denoted by I µ [n]. In a paper by P. , I 3 [n] is determined completely. In this paper we completely determine I 4 [n] for n ≥ 16. For n ≤ 16, we find out most of the elements of I 4 [n].

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Cited by 15 publications
(37 citation statements)
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“…As IS There does not exist a large set of idempotent latin squares of order n = 6, however there does exist a (4,5,6)-latin trade given by: (2,3,4,5) • (1, 4, 5, 3) (5, 2, 1, 4) (3, 5, 2, 1) (4,1,3,2) • (3, 2, 5, 4) (6, 3, 4, 5) (4, 5, 2, 6) (5, 6, 3, 2) (2,4,6,3) (1, 4, 5, 3) (4, 5, 3, 6) (5, 1, 6, 4) • (6, 3, 1, 5) (3, 6, 4, 1) Applying Theorem 7 of [7] to the combination of a (3,5,6) …”
Section: Resultsmentioning
confidence: 99%
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“…As IS There does not exist a large set of idempotent latin squares of order n = 6, however there does exist a (4,5,6)-latin trade given by: (2,3,4,5) • (1, 4, 5, 3) (5, 2, 1, 4) (3, 5, 2, 1) (4,1,3,2) • (3, 2, 5, 4) (6, 3, 4, 5) (4, 5, 2, 6) (5, 6, 3, 2) (2,4,6,3) (1, 4, 5, 3) (4, 5, 3, 6) (5, 1, 6, 4) • (6, 3, 1, 5) (3, 6, 4, 1) Applying Theorem 7 of [7] to the combination of a (3,5,6) …”
Section: Resultsmentioning
confidence: 99%
“…We can thus interpret the results of [1] in terms of 3-way latin trades and combine them with Theorem 3.4.6 to yield: • k ∈ {0, 9}, for λ = 3;…”
Section: Packing Constructionmentioning
confidence: 96%
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