2016
DOI: 10.1214/15-aap1100
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The symplectic geometry of closed equilateral random walks in 3-space

Abstract: A closed equilateral random walk in 3-space is a selection of unit length vectors giving the steps of the walk conditioned on the assumption that the sum of the vectors is zero. The sample space of such walks with $n$ edges is the $(2n-3)$-dimensional Riemannian manifold of equilateral closed polygons in $\mathbb{R}^3$. We study closed random walks using the symplectic geometry of the $(2n-6)$-dimensional quotient of the manifold of polygons by the action of the rotation group $\operatorname {SO}(3)$. The basi… Show more

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Cited by 32 publications
(44 citation statements)
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“…We remark that the quaternion method has been generalized to a fast algorithm for generating equilateral random polygons through symplectic geometry. [32,33,34] We analytically show that the ratio of the gyration radius to the hydrodynamic radius of a topological polymer, R G /R H , is characterized by the variance of the probability distribution function of the distance between two segments of the polymer. In particular, we argue that the ratio decreases if the variance becomes small.…”
Section: Introductionmentioning
confidence: 99%
“…We remark that the quaternion method has been generalized to a fast algorithm for generating equilateral random polygons through symplectic geometry. [32,33,34] We analytically show that the ratio of the gyration radius to the hydrodynamic radius of a topological polymer, R G /R H , is characterized by the variance of the probability distribution function of the distance between two segments of the polymer. In particular, we argue that the ratio decreases if the variance becomes small.…”
Section: Introductionmentioning
confidence: 99%
“…In the same ongoing discussion in which Woolhouse posed his versions of the obtuse triangle problem, J. J. Sylvester in 1864 asked for the probability that four points "taken at random in a plane" formed the vertices of a reentrant (embedded, but not convex) quadrilateral [25]. 6 Various solutions were proposed by Cayley [24, footnote 64(b)], De Morgan [7, pp. 147-148], and others, with answers including (at least) 1/4, 35/12π 2 , 3/8, 1/3, and 1/2 [14].…”
Section: Sylvester's 4-point Problem and Quadrilateralsmentioning
confidence: 99%
“…In this section, we will discuss the probability that a random equilateral hexagon is knotted. It has been proven that at least 1 3 of hexagons with total length 2 are unknotted [8]. Using action-angle coordinates and Calvo's geometric invariant curl, Cantarella and Shonkwiler [8] prove that at least 1 2 of the space of equilateral hexagons consists of unknots.…”
Section: Knotting Probability Of Hexagonal Trefoilsmentioning
confidence: 99%