2002
DOI: 10.1007/s00013-002-8261-x
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The strong two-generator property in rings of integer-valued polynomials determined by finite sets

Abstract: Let D be an integral domain and E = {e 1 , . . . , e k } a finite nonempty subset of D. Then Int(E, D) has the strong two-generator property if and only if D is a Bezout domain. If D is a Dedekind domain which is not a principal ideal domain, then we characterize which elements of Int(E, D) are strong two-generators.Let D be an integral domain with quotient field K and E ֤ D a subset of D. We letdenote the much studied ring of integer-valued polynomials on D with respect to the subset E (for ease of notation, … Show more

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Cited by 10 publications
(11 citation statements)
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“…. , a r } of D, and let Int(E, D) = {f ∈ Q[X] : f (E) D}, the ring of integer-valued polynomials on D with respect to the subset E. As in [9], we fix polynomials F = [2] and [3], this is called the almost strong Skolem property. In [9] this is called the strong Hilbert property.…”
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confidence: 99%
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“…. , a r } of D, and let Int(E, D) = {f ∈ Q[X] : f (E) D}, the ring of integer-valued polynomials on D with respect to the subset E. As in [9], we fix polynomials F = [2] and [3], this is called the almost strong Skolem property. In [9] this is called the strong Hilbert property.…”
mentioning
confidence: 99%
“…In [3,Theorem 4], Chapman, Loper, and Smith show that, for finite non-empty E, the integral domain D is a Bezout domain if and only if Int(E, D) has the strong 2-generator property. Thus, both D and Int(E, D) must be Prüfer domains in this case.…”
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confidence: 99%
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“…This case is well described by McQuillan [26] for subsets of any integral domain (see also [8, Exercises IV.1, V.2, VI.20, VIII.25 and VIII.28] and [17]). For finite subsets of a valued field K, one can say a bit more.…”
Section: S Finitementioning
confidence: 53%