1998
DOI: 10.1006/jfan.1998.3334
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The Stable Rank of Topological Algebras and a Problem of R. G. Swan

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Cited by 14 publications
(37 citation statements)
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“…We show that this is indeed the case for the higher connected stable ranks. The next result improves a result of Badea [2,Theorem 4.15] in several ways. First and foremost, it removes the commutativity assumption.…”
Section: Swan's Problem For the Higher Connected Stable Rankssupporting
confidence: 80%
See 1 more Smart Citation
“…We show that this is indeed the case for the higher connected stable ranks. The next result improves a result of Badea [2,Theorem 4.15] in several ways. First and foremost, it removes the commutativity assumption.…”
Section: Swan's Problem For the Higher Connected Stable Rankssupporting
confidence: 80%
“…Most significantly, bsr(A) = bsr(B) whenever A is a "smooth" subalgebra of a C * -algebra B [2, Theorem 1.1, Corollary 4.10]. Also, csr(A) = csr(B) for A a dense and spectral subalgebra of a commutative Banach algebra B [2,Theorem 4.15]. As for the results concerning the topological stable rank [2,Theorem 4.13,Corollary 4.14], the hypotheses are unnatural.…”
Section: Introductionmentioning
confidence: 98%
“…The GRS-condition is equivalent to the spectral invariance of A 1 v (Λ, c) in C * (Λ, c) and therefore by Badea's result [1] Λ, c)). By Theorem 1.5 in [4] we know that tsr C * (Λ, c) = 1 for Λ completely irrational.…”
Section: Theorem 25 Let λ Be Completely Irrational and V A Grs-weigmentioning
confidence: 86%
“…1.1], says the following: if A is a dense and spectral Banach * -subalgebra of a C * -algebra B, and if A is closed under C ∞ -functional calculus for self-adjoint elements, then bsr A = bsr B. This applies, for instance, to dense subalgebras coming from derivations [3,Cor. 4.10].…”
Section: Swan's Problemmentioning
confidence: 96%