2012
DOI: 10.4171/ggd/158
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The simultaneous conjugacy problem in groups of piecewise linear functions

Abstract: Guba and Sapir asked if the simultaneous conjugacy problem was solvable in Diagram Groups or, at least, for Thompson's group F . We give a solution to the latter question using elementary techniques which rely purely on the description of F as the group of piecewise linear orientationpreserving homeomorphisms of the unit interval. The techniques we develop extend the ones used by Brin and Squier allowing us to compute roots and centralizers as well. Moreover, these techniques can be generalized to solve the sa… Show more

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Cited by 20 publications
(67 citation statements)
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“…This result will often be needed along the present paper. [14]). Let η, ζ be dyadic rationals, let α, β ∈ Q ∩ (η, ζ) written in the form α = 2 t m n and β = 2 k p q with t, k ∈ Z and m, n, p, q odd integers such that (m, n) = (p, q) = 1, and let η < α 1 < · · · < α r < ζ and η < β 1 < · · · < β r < ζ be two finite sequences of rational numbers.…”
Section: Automorphisms and Transitivity On Dyadicsmentioning
confidence: 99%
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“…This result will often be needed along the present paper. [14]). Let η, ζ be dyadic rationals, let α, β ∈ Q ∩ (η, ζ) written in the form α = 2 t m n and β = 2 k p q with t, k ∈ Z and m, n, p, q odd integers such that (m, n) = (p, q) = 1, and let η < α 1 < · · · < α r < ζ and η < β 1 < · · · < β r < ζ be two finite sequences of rational numbers.…”
Section: Automorphisms and Transitivity On Dyadicsmentioning
confidence: 99%
“…We now deal with the equation z = g −1 yg for y, z ∈ EP 2 and g ∈ F . The argument will make use of techniques and statements in [14] and refer often to that paper. Subsection 4.1 in [14] shows that, if z = g −1 yg with y, z, g ∈ PL 2 (I), then there exists ε > 0 depending only on y and z such that g is linear inside [0, ε] 2 ; the box [0, ε] 2 is called an initial linearity box.…”
Section: 4mentioning
confidence: 99%
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