2016
DOI: 10.1140/epjc/s10052-016-4535-5
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The sigma meson from QCD sum rules for large- $$N_c$$ N c Regge spectra

Abstract: The QCD sum rules in the large-N c limit for the light non-strange vector, axial and scalar mesons are considered assuming a string-like linear spectrum for the radially excited states. We propose an improved method for combined analysis of these channels that gives a reasonable description of the observed spectrum. In the vector-axial case, fixing the pion decay constant and the gluon condensate we obtain more or less physical values for the masses of ground states and the quark condensate. Thus a typical nee… Show more

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Cited by 10 publications
(14 citation statements)
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“…[74] was (in GeV (crosses) mesons according to the Refs. [92,109]. The horizontal lines are drawn to distinguish better the position of scalar resonances [91].…”
Section: Discussionmentioning
confidence: 99%
See 1 more Smart Citation
“…[74] was (in GeV (crosses) mesons according to the Refs. [92,109]. The horizontal lines are drawn to distinguish better the position of scalar resonances [91].…”
Section: Discussionmentioning
confidence: 99%
“…It means that if a radial trajectory is fitted using only the excited states and after that the mass of ground state is predicted, the prediction will appreciably overestimate the real mass (see, e.g., the discussions in Ref. [92] and the Fig. 6 in the Appendix E).…”
Section: Chiral Symmetry Breakingmentioning
confidence: 99%
“…Within the latter assumption, the mass of σ-meson can be derived as a function of the intercept parameter m 2 s (we refer to Ref. [8] for details, the chiral limit is considered),…”
Section: Scalar Sum Rules: Some Resultsmentioning
confidence: 99%
“…Within the latter assumption, the mass of σ-meson can be derived as a function of the intercept parameter m 2 s (we refer to Ref. [6] for details, the chiral limit is considered),…”
Section: Introductionmentioning
confidence: 99%
“…1 [6]. The mass of the first radially excited state M S (1) is rather stable and seems to reproduce the mass of a 0 (1450)-meson, M a 0 (1450) = 1474 ± 19 MeV [7].…”
Section: Introductionmentioning
confidence: 99%