2017
DOI: 10.1007/s00574-017-0058-4
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The Reeb Graph of a Map Germ from $$\mathbb {R}^3$$ R 3 to $$\mathbb {R}^2$$ R

Abstract: We consider the topological classification of finitely determined map germs [ f ] : (R 3 , 0) → (R 2 , 0) with f −1 (0) = {0}. The case f −1 (0) = {0} was treated in another recent paper by the authors. The main tool used to describe the topological type is the link of [ f ], which is obtained by taking the intersection of its image with a small sphere S 1 δ centered at the origin. The link is a stable map γ f : N → S 1 , where N is diffeomorphic to a sphere S 2 minus 2L disks. We define a complete topological… Show more

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Cited by 4 publications
(7 citation statements)
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“…If rank(α) = 1 we have that j 2 f (0) ∼ (x, y, a 1 z 2 + a 2 xz + a 3 yz, 0), obtaining, following an analogous procedure to the previous case the A 2 -orbits (x, y, z 2 , 0) and (x, y, xz, 0). Finally, if rank(α) = 0 we get that j 2 f (0) ∼ (x, y, 0, 0).…”
Section: Map Germs Of Fold Typementioning
confidence: 86%
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“…If rank(α) = 1 we have that j 2 f (0) ∼ (x, y, a 1 z 2 + a 2 xz + a 3 yz, 0), obtaining, following an analogous procedure to the previous case the A 2 -orbits (x, y, z 2 , 0) and (x, y, xz, 0). Finally, if rank(α) = 0 we get that j 2 f (0) ∼ (x, y, 0, 0).…”
Section: Map Germs Of Fold Typementioning
confidence: 86%
“…By induction, χ(Γ ) = 1 and hence χ(Γ) = (v − 1) + 1 − ((v − 2) + 1) = 1, since we are adding a final vertex. We use again induction on the number of vertices to prove (2). For dual graphs with 1 and 2 vertices it is clear from example 4.3.…”
Section: Mosaics and Dual Graphsmentioning
confidence: 99%
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