We prove that the minimum number of Hamilton cycles in a Hamiltonian threshold graph of order
n is
2
⌊
(
n
−
3
)
∕
2
⌋ and this minimum number is attained uniquely by the graph with degree sequence
n
goodbreakinfix−
1
goodbreakinfix,
n
goodbreakinfix−
1
goodbreakinfix,
n
goodbreakinfix−
2
,
…
,
⌈
n
∕
2
⌉
goodbreakinfix,
⌈
n
∕
2
⌉
,
…
,
3,2 of
n
goodbreakinfix−
2 distinct degrees. This graph is also the unique graph of minimum size among all Hamiltonian threshold graphs of order
n.