1987
DOI: 10.1017/s001309150002825x
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The natural partial order on an abundant semigroup

Abstract: In this paper we will study the properties of a natural partial order which may be defined on an arbitrary abundant semigroup: in the case of regular semigroups we recapture the order introduced by Nambooripad [24]. For abelian PP rings our order coincides with a relation introduced by Sussman [25], Abian [1,2] and further studied by Chacron [7]. Burmistrovic [6] investigated Sussman's order on separative semigroups. In the abundant case his order coincides with ours: some order theoretic properties of such se… Show more

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Cited by 61 publications
(30 citation statements)
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“…The next result, which is due to Lawson [16], gives a characterization of the natural partial order on an abundant semigroup. Lemma 4.5.…”
Section: Multiplicative Basis B and Semigroup Smentioning
confidence: 94%
See 1 more Smart Citation
“…The next result, which is due to Lawson [16], gives a characterization of the natural partial order on an abundant semigroup. Lemma 4.5.…”
Section: Multiplicative Basis B and Semigroup Smentioning
confidence: 94%
“…An abundant semigroup S is called idempotent connected (IC) [17], if for all a 2 S , a 2 R a .S / \ E.S / and A semigroup S is said to satisfy the regularity condition [16] if for all idempotents e and f of S the element ef is regular. If this is the case, the sandwich set S.e; f / D fg 2 V .ef / \ E.S / j ge D fg D gg of idempotents e and f is non-empty, and takes the form…”
Section: Preliminariesmentioning
confidence: 99%
“…First, we state some known results and notations which will be frequently used throughout the paper. [9], Lawson define a natural partial order relation " ≤ " on an abundant semigroup S as follows: (∀a, b ∈ S) a ≤ b if and only if there are idempotents e, f ∈ S, such that a = eb = bf.…”
Section: Preliminariesmentioning
confidence: 99%
“…(B2) if for all a ∈ S, e ∈ E(S), e ≤ a * , then there is an element f ∈ E(S 1 ) such that e = (f a) * , where " ≤ " is a natural partial order on E(S) ( i.e., (∀e, f ∈ E(S)) e ≤ f ⇔ e = ef = f e (see, [9])).…”
Section: Introductionmentioning
confidence: 99%
“…There have been numerous attempts to extend this ordering from Es to all of S defining it by means of the multiplication of S and postulating that its restriction to Es coincides with the partial order (1) (see Burgess and Raphael [2], Hartwig [4], Lawson [8], McAlister [9] and Nambooripad [10]). The reason for the interest in such natural orders lies in the obvious fact that such an ordering can provide additional information on a given semigroup since it reflects its multiplication in a particular way.…”
Section: Introductionmentioning
confidence: 99%