1935
DOI: 10.1021/cr60057a001
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The Mechanism of Some Important Organic Reactions.

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Cited by 24 publications
(7 citation statements)
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“…A yield of 1.2 moles of lactic acid (60°Jo yield) has been obtained from glucose upon treatment with benzyl-trimethyl-ammonium hydroxide [ 14,37,41 ] . The formation of the glyceraldehyde in the alkaline solution is explained by the weakening of the C1-C~ bond in the C.-C2 enediol formed from glucose in alkali, which then undergoes the C,-Ct cleavage [ 51 ] .…”
Section: The Peeled-off Glucose Unitsmentioning
confidence: 99%
“…A yield of 1.2 moles of lactic acid (60°Jo yield) has been obtained from glucose upon treatment with benzyl-trimethyl-ammonium hydroxide [ 14,37,41 ] . The formation of the glyceraldehyde in the alkaline solution is explained by the weakening of the C1-C~ bond in the C.-C2 enediol formed from glucose in alkali, which then undergoes the C,-Ct cleavage [ 51 ] .…”
Section: The Peeled-off Glucose Unitsmentioning
confidence: 99%
“…Schmidt has formulated a double-bond rule, maintaining that the double bond between two carbon atoms strengthens the adjacent single bonds and weakens the next following (139). The mechanism of bond scission was later considered from the electronic standpoint (140). Cracking of alkanes was explained in the following way (140):…”
Section: Chs Chmentioning
confidence: 99%
“…The mechanism of bond scission was later considered from the electronic standpoint (140). Cracking of alkanes was explained in the following way (140):…”
Section: Chs Chmentioning
confidence: 99%
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“…Hence, the fragmentation cannot take place as indicated. Furthermore, the work of Schmidt (43,53) and others clearly shows that the formation of the double bond in a compound weakens the single bond of It is conceivable that the enediols of glyceraldehyde, erythrose, and arabinose may rearrange to the normal form and that in the cases of erythrose and arabinose these normal forms may undergo a different enolization and subsequent fragmentation. It is also clear that D-arabinose 2,3-enediol in equation 3' may undergo fragmentation into formaldehyde and erythrose 2,3-enediol before any rearrangement takes place to the normal form.…”
Section: Degradation Of Carbohydrates In Alkaline Solutionmentioning
confidence: 99%