2011
DOI: 10.1007/s10959-011-0364-5
|View full text |Cite
|
Sign up to set email alerts
|

The Length of the Longest Increasing Subsequence of a Random Mallows Permutation

Abstract: The Mallows measure on the symmetric group Sn is the probability measure such that each permutation has probability proportional to q raised to the power of the number of inversions, where q is a positive parameter and the number of inversions of π is equal to the number of pairs i < j such that πi > πj. We prove a weak law of large numbers for the length of the longest increasing subsequence for Mallows distributed random permutations, in the limit that n → ∞ and q → 1 in such a way that n(1 − q) has a limit … Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
4
1

Citation Types

1
53
0

Year Published

2014
2014
2023
2023

Publication Types

Select...
5

Relationship

0
5

Authors

Journals

citations
Cited by 43 publications
(54 citation statements)
references
References 21 publications
1
53
0
Order By: Relevance
“…As explained before Theorem 1.2 above, one may again employ the idea of placing n(1 − q)/β disjoint squares of side length β/(1 − q) along the diagonal as in Figure 3. Since we expect the distribution of the points in each such square to be close to that of the Mallows µ β/(1−q),q measure, the results of [24] suggest that the typical order of magnitude of the length of the longest decreasing subsequence in each square is of order 1/ √ 1 − q. When considering decreasing subsequences we cannot concatenate the subsequences of disjoint squares, since the overall trend of the points is positive.…”
Section: Below) In Particular Lis(π) Is Distributed As Lds(π R )mentioning
confidence: 89%
See 4 more Smart Citations
“…As explained before Theorem 1.2 above, one may again employ the idea of placing n(1 − q)/β disjoint squares of side length β/(1 − q) along the diagonal as in Figure 3. Since we expect the distribution of the points in each such square to be close to that of the Mallows µ β/(1−q),q measure, the results of [24] suggest that the typical order of magnitude of the length of the longest decreasing subsequence in each square is of order 1/ √ 1 − q. When considering decreasing subsequences we cannot concatenate the subsequences of disjoint squares, since the overall trend of the points is positive.…”
Section: Below) In Particular Lis(π) Is Distributed As Lds(π R )mentioning
confidence: 89%
“…Theorem 1.1 and the results in Section 2.1 give rigorous meaning to such statements). Thus the parameters fall in the regime of [24] and according to their results, the typical length of the longest increasing subsequence in each square is of order 1/ √ 1 − q. We may thus create an increasing subsequence with length of order n √ 1 − q by concatenating the longest increasing subsequences in each of the n(1 − q)/β squares.…”
Section: Below) In Particular Lis(π) Is Distributed As Lds(π R )mentioning
confidence: 97%
See 3 more Smart Citations