2014
DOI: 10.1016/j.laa.2014.05.041
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The largest subsemilattices of the endomorphism monoid of an independence algebra

Abstract: An algebra A is said to be an independence algebra if it is a matroid algebra and every map α : X → A, defined on a basis X of A, can be extended to an endomorphism of A. These algebras are particularly well behaved generalizations of vector spaces, and hence they naturally appear in several branches of mathematics such as model theory, group theory, and semigroup theory.It is well known that matroid algebras have a well defined notion of dimension. Let A be any independence algebra of finite dimension n, with… Show more

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Cited by 6 publications
(11 citation statements)
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“…Symmetrically, there exists t ∈ GL(i, F ) × GL(j, F ) such that At = A(s 3 , s 4 ) −1 (t 3 , t 4 ), for all A ∈ GL(i, F ) × GL(j, F ). Now, (5) shows that in the group GL(i, F ) × GL(j, F ), we have t = s −1 . Thus, in GL(i, F ) × GL(j, F ),…”
Section: Thenmentioning
confidence: 97%
See 1 more Smart Citation
“…Symmetrically, there exists t ∈ GL(i, F ) × GL(j, F ) such that At = A(s 3 , s 4 ) −1 (t 3 , t 4 ), for all A ∈ GL(i, F ) × GL(j, F ). Now, (5) shows that in the group GL(i, F ) × GL(j, F ), we have t = s −1 . Thus, in GL(i, F ) × GL(j, F ),…”
Section: Thenmentioning
confidence: 97%
“…Possibly the best approach to attack Problem 8.10 is to rely on the classification theorem of these algebras ( [26,69,70]), as in [5].…”
Section: Problemsmentioning
confidence: 99%
“…Indeed, we have 4 ∼ p 3 (since 4 = 1 · 4 and 3 = 4 · 1) and 3 ∼ p 5 (since 3 = 1 · 5 and 5 = 5 · 1), but there are no x, y such that 4 = xy and 5 = yx. It is straightforward to check that ∼ p is the symmetric and reflexive closure of {(1, 2), (3,4), (3,5)}, that ∼ * p = ∼ tr , and that ∼ c = ∼ o has equivalence classes {0, 1, 2} and {3, 4, 5}. Thus we have the claimed strict inclusions.…”
Section: Conjugacy In Epigroups and Epigroup Elementsmentioning
confidence: 76%
“…Now this graph can be found as a subgraph of Γ, as the union of two butterflies sharing a triangle; therefore the homomorphism can be realised as an endomorphism of Γ of rank 7, with kernel classes of sizes (10,10,5,5,5,5,5). The endomorphisms of ranks 5 and 3 can now be found by folding in one or both "wings" in the above figure.…”
Section: Rank 5 (And 7)mentioning
confidence: 99%
“…Problem 9.10 Solve the analogue of Problem 9.9 for independence algebras (for definitions and fundamental results see [3,9,10,11,5,23,27,28,30])…”
Section: Problem 94mentioning
confidence: 99%