1965
DOI: 10.1119/1.1971931
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The Kepler Problem in Two-Dimensional Momentum Space

Abstract: Fock studied the hydrogen atom problem in momentum space by projecting the space into a 4-dimensional hyperspherical space. He found that as a consequence of the symmetry of the problem in this space the eigenfunctions are the R4 spherical harmonics and that the eigenvalues are determined only by the principal quantum number n. In this paper we note that if his method is applied to the 2-dimensional Kepler problem in momentum space, the eigenfunctions are R3 spherical harmonics, Ylm, and the eigenvalues are de… Show more

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Cited by 33 publications
(23 citation statements)
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“…., (0, ±N ), and the degeneracy is d N = 2N + 1. These results are well known [13][14][15][16][17][18]. 2. ν = 0, m 0 = 0.…”
Section: Bound Statessupporting
confidence: 65%
“…., (0, ±N ), and the degeneracy is d N = 2N + 1. These results are well known [13][14][15][16][17][18]. 2. ν = 0, m 0 = 0.…”
Section: Bound Statessupporting
confidence: 65%
“…In fact, as Monkhorst and Jeriorski have pointed out [4], the many-center one-particle Coulomb problem in reciprocal space reduces essentially to the problem of evaluating these integrals. In an early paper [4], Shibuya and Wulfman developed a method for their evaluation based on the R4 Wigner coefficients. In this paper we shall discuss an alternative method based on a transform defined by the relationship 1 / aS2 eik'Rf(u) =jT(t) (52) 2~ 2 with t = koR.…”
Section: S2/~m(r ) =-[ Do E Ik'r Rn*-llm(u) Yn-llm(u)mentioning
confidence: 97%
“…It has been shown by a number of authors [4][5][6]] that Fock's approach can be generalized in such a way as to yield solutions to the reciprocal-space Schr6dinger equation for a charged particle moving in the many-center potential: …”
Section: Many-center Coulomb Potentialsmentioning
confidence: 99%
“…It is p 2 D and therefore must be the (202) state. The three P states, p 2 P, spP, and psP transform like linear combinations of (111), (1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11) and (201). The (111) and (1-11) states have zero coupling with the (202) state for the reason mentioned above, and thus we may determine the (111) and (1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11) states by means of the equations…”
Section: A Mathematicalmentioning
confidence: 99%