2012
DOI: 10.48550/arxiv.1206.2380
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The Highest Dimensional Stochastic Blockmodel with a Regularized Estimator

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Cited by 4 publications
(3 citation statements)
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“…First, although our recovery guarantees match those previously identified in the literature, these bounds may not be the best possible. Rohe et al [46] recently established that an N -node random graph sampled from the Stochastic Blockmodel can be partitioned into dense subgraphs of size Ω(log 4 N ) using a regularized maximum likelihood estimator. It is unclear if such a bound can be attained for our relaxation.…”
Section: Resultsmentioning
confidence: 99%
“…First, although our recovery guarantees match those previously identified in the literature, these bounds may not be the best possible. Rohe et al [46] recently established that an N -node random graph sampled from the Stochastic Blockmodel can be partitioned into dense subgraphs of size Ω(log 4 N ) using a regularized maximum likelihood estimator. It is unclear if such a bound can be attained for our relaxation.…”
Section: Resultsmentioning
confidence: 99%
“…However, all in all, I am not aware of any estimator for the stochastic blockmodel that works whenever the number of blocks is small compared to the number of nodes. The best result till date is in the very recent manuscript of Rohe et al [86], who prove that a penalized likelihood estimator works whenever k is comparable to n "up to log factors." The following theorem says that the USVT estimator M gives a complete solution to the estimation problem in the stochastic blockmodel if k ≪ n, with no further conditions required.…”
Section: The Stochastic Blockmodelmentioning
confidence: 99%
“…. , K. For example, the submodel may restrict H so that H(Z i , Z j ) depends only on whether Z i = Z j or not; this assumption could reflect homogeneity of the classes, and is explored in Rohe, Qin and Fan (2012). This submodel is identifiable under ordering of π, and the latent structure might be more gracefully described as a partition, that is, a variable X ∈ {0, 1} n×n satisfying X(i, j) = 1 iff Z i = Z j .…”
Section: Preliminariesmentioning
confidence: 99%