The 6 He+ 6 Li elastic scattering and transfer reactions have been studied using a 17.0 MeV 6 He beam. The measurements show large cross-sections for α transfer reactions leading to some states at high excitations (6 ≤ Ex ≤ 11 MeV) in 10 Be. The results support suggestions that these states have a molecule-like structure and may belong to the same rotational band.Introduction. -The 6 He nucleus exhibits halo structure with two loosely bound neutrons and an α-particle core. One may expect that by adding an α-particle to this loose object a structure could be formed resembling the H 2 molecule. In this case the "covalent" bonding of two α-particles would be achieved by two neutrons. In accordance with the ideas of clustering in light nuclei [1, 2] the 10 Be states of this nature could be expected in the vicinity of the thresholds for 2α + 2n (8.39 MeV) and α + 6 He (7.41 MeV) decays (fig. 1). A possible candidate could be the second 0 + state at 6.18 MeV, which cannot be described by the shell model approach (see, e.g., [3][4][5]), but fits well into the three-cluster picture (α + α + 2 n) as discussed in [6,7]. Our results on the 7 Li + 7 Li reaction [8] have shown that the 10 Be state at 10.2 MeV decays into the α + 6 He channel (but not into n + 9 Be). We then speculated that this state may be the third, 4 + , member of a rotational band based on the band head state 0 + 2 at 6.18 MeV and the 2 + 3 state at 7.54 MeV. The small energy separation between them would then imply a large moment of inertia, i.e. they would be very extended objects. Von Oertzen [9] with his ideas on nuclear dimers independently suggested the existence of this band. However, his third member would be the 10.6 MeV state, which, according to our results, has a very weak (if any) α + 6 He branching but intense n + 9 Be decay.