“…Using the auxiliary data from Wagman et al (1968) and 6.HfO(HF• 20H 2 0, aq, 298)=-77.004 kcal mol-I (Settle, Greenberg, and Hubbard, 1971;Johnson, Smith, and Hubbard, 1971) From the enthalpy change . for reaction 9-1 determined by Scott, Good, and Waddington (1955), one can calculate 6.Hr(C 2F-4, poly, 298)=-199.0± 0.9 kcal mol-to Incorporating this value with 6.HrO(298) for reaction 9-6 yields 6.HF(CF .. , g, 298)=-222.9± 0.9 kcal mol-t. Domalski and Armstrong (1967) studied the same reaction (9-6) but with 15 atm fluorine which, they report; suqJn:~88ed Lhe fUrIllaLiull uf higher pedluolOalkanes. They obtained 6.HrO(298)=-247.92±0.07 kcal mol-I [compare to 6.HrO(298)=-246.84 kcal mol-1 of Wood, Lagow, and Margrave (1967)].…”