1989
DOI: 10.1016/0196-6774(89)90012-6
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The hamiltonian cycle problem is linear-time solvable for 4-connected planar graphs

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Cited by 80 publications
(47 citation statements)
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“…Finding the separating triangles and making the graphs 4-connected takes linear time [3]. A Hamiltonian cycle in a 4-connected planar graphs can be found in linear time [4].…”
Section: Making the Graphs 4-connectedmentioning
confidence: 99%
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“…Finding the separating triangles and making the graphs 4-connected takes linear time [3]. A Hamiltonian cycle in a 4-connected planar graphs can be found in linear time [4].…”
Section: Making the Graphs 4-connectedmentioning
confidence: 99%
“…Let G be the subgraph of G induced on vertices {1, 2, 3, 4, 5}, and G be the subgraph of G induced on vertices {2, 6, 7, 8, 9}. Since G is 3-connected fixing the outer-face fixes an embedding for G. With the given outer-face of G, the path P contains two crossings: one involving (2,4), and the other one involving (6,8). Graph G has six faces and unless we change the outer-face of G such that it contains the edge (1, 3) or (3,5), the edge (2, 4) is involved in a crossing in the path.…”
Section: Theoremmentioning
confidence: 99%
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“…Testing all possible edges e = (v, w) on the outer face, we could request a hamiltonian path, which is a well-known NP-complete problem even on planar graphs. On the other hand, we know of a linear-time algorithm to find external hamiltonian cycles by Chiba and Nishizeki [5], if the graph is four-connected. Since the graphs we consider are triangulated, the problematic cases appear if there are separating triangles, namely cycles of length 3 which do not circumscribe single faces.…”
Section: The General Casementioning
confidence: 99%
“…If G is 4-connected we can find a Hamiltonian cycle and hence a (nearly) perfect matching in linear time [CN89]. If G is not 4-connected the basic idea is to find a matching in every block separately and combine them to a matching in G. Let G 1 , .…”
Section: The 4-block Tree Is a Pathmentioning
confidence: 99%