2017
DOI: 10.1007/s12220-017-9957-2
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The Geometry of m-Hyperconvex Domains

Abstract: We study the geometry of m-regular domains within the CaffarelliNirenberg-Spruck model in terms of barrier functions, envelopes, exhaustion functions, and Jensen measures. We prove among other things that every mhyperconvex domain admits an exhaustion function that is negative, smooth, strictly m-subharmonic, and has bounded m-Hessian measure.

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Cited by 23 publications
(19 citation statements)
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“…Then it is also locally m-hyperconvex. By Theorem 3.3 in [2], we know that Ω must be globally m-hyperconvex. Thus, there exists ψ ∈ SH m (Ω) ∩ C(Ω), ψ ≡ 0, such that ψ| ∂Ω = 0.…”
Section: Proofmentioning
confidence: 99%
See 1 more Smart Citation
“…Then it is also locally m-hyperconvex. By Theorem 3.3 in [2], we know that Ω must be globally m-hyperconvex. Thus, there exists ψ ∈ SH m (Ω) ∩ C(Ω), ψ ≡ 0, such that ψ| ∂Ω = 0.…”
Section: Proofmentioning
confidence: 99%
“…We shall need the following lemma. Since Ω is also m-hyperconvex there exists a smooth and strictly m-subharmonic exhaustion function ϕ for Ω (see [2]). Let M > 1 be a constant large enough so that for all z ∈ K ϕ(z) − 1 > M ψ(z) .…”
Section: An Extension Theoremmentioning
confidence: 99%
“…where ρ ∈ E 0,m (Ω) ∩ C ∞ (Ω) is a strictly m-subharmonic exhaustion function of Ω (see [2]). Hence, to prove u = v it is enough to show that…”
Section: Lemma 2 Ifmentioning
confidence: 99%
“…Thus, we can characterize those functions f : Ω → Ω ′ such that condition (1), or (2), holds. Even though the work of Jacobi [40] is certainly an early encounter with harmonic morphisms as we know them today, the geometrical idea behind the equivalence of (2) and (3) is due to Johann Carl Friedrich Gauß [28] from 1822 (published in [29]; for an English translation see [30,31]). In modern times, the above result was used for example in analytic multivalued function theory (see e.g.…”
Section: Introductionmentioning
confidence: 99%
“…On the other hand, there has been some progress obtaining a Poisson type formula for SH k using Choquet theory and representing measures, instead of Poletsky disks (see e.g. Theorem 2.8 in [2] and the references therein).…”
Section: Introductionmentioning
confidence: 99%