2013
DOI: 10.7494/opmath.2013.33.2.345
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The forwarding indices of graphs - a survey

Abstract: Abstract. A routing R of a connected graph G of order n is a collection of n(n − 1) simple paths connecting every ordered pair of vertices of G. The vertex-forwarding index ξ(G, R) of G with respect to a routing R is defined as the maximum number of paths in R passing through any vertex of G. The vertex-forwarding index ξ(G) of G is defined as the minimum ξ(G, R) over all routings R of G. Similarly, the edge-forwarding index π(G, R) of G with respect to a routing R is the maximum number of paths in R passing t… Show more

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Cited by 6 publications
(7 citation statements)
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“…To our surprise, we could not find the following result in the literature, moreover in the recent survey [11] the best bounds for cubic graphs were provided by shuffle exchange graphs, and more generally, for bounded degree graphs the best bounds known are derived using de Bruijn graphs. Those bounds are rather good since they differ from the lower bound only by a relatively small (always lesser than 2) constant factor.…”
Section: 3mentioning
confidence: 87%
See 3 more Smart Citations
“…To our surprise, we could not find the following result in the literature, moreover in the recent survey [11] the best bounds for cubic graphs were provided by shuffle exchange graphs, and more generally, for bounded degree graphs the best bounds known are derived using de Bruijn graphs. Those bounds are rather good since they differ from the lower bound only by a relatively small (always lesser than 2) constant factor.…”
Section: 3mentioning
confidence: 87%
“…For ∆ = 3, when e = 3n 2 , graphs such like the shuffle exchange provide deterministic generic constructions for which π(G) ≤ n log 2 n (this is a folk result for people studying network throughput, one may see [26]). Since using the Moore bound (that bound claims by direct counting that the average distance in a ∆ bounded degree graph is of order log ∆−1 (n), see as example [16]) one can prove that π * (n, 3n…”
Section: Minimally Congested Graphsmentioning
confidence: 97%
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“…If s = √ n, then q = ⌊n/s⌋ = √ n and by (27) we obtain − → π (C n (1, s)) ≤ ( √ n(n − ǫ(s))/8. If √ n + 1 ≤ s < n/2, then by (28) and (29) we have − → π (C n (1, s)) ≤ (s(n + r + 2) − ǫ(s)q)/8 = (s 2 (n + r + 2) − ǫ(s)(n − r))/8s.…”
Section: Ring Linksmentioning
confidence: 96%