“…It implies that σ(S + ) ⊂ Ω 0 . By Proposition 2.3 in [5], moreover, we have that S − ∈ B n (Ω 0 ). Set Ω = Ω 0 \σ(S + ).…”
Section: Proof Of the Theorem And Its Corollariesmentioning
confidence: 82%
“…Hence, S + cannot be a Cowen-Douglas operator. When S * + is a Cowen-Douglas operator has been characterized in [5]. In this note, we will prove the following theorem.…”
Section: Introductionmentioning
confidence: 94%
“…In [5], σ e (S + ) and the indices associated with all holes in σ e (S + ) have been described. For convenience, we draw the following conclusions.…”
“…By the Riesz decomposition theorem, if σ(T ) is not connected, then T is not strongly irreducible. For a unilateral operator weighted shift S + , it follows from Theorem 3.1 in [5] that if σ e (S + ) is not connected, then S + is not strongly irreducible. For a bilateral operator weighted shift S, however, the following example shows that a similar claim is false even though S is a Cowen-Douglas operator.…”
Section: Corollary 1 Let S Be a Bilateral Scalar Weighted Shift Thementioning
“…It implies that σ(S + ) ⊂ Ω 0 . By Proposition 2.3 in [5], moreover, we have that S − ∈ B n (Ω 0 ). Set Ω = Ω 0 \σ(S + ).…”
Section: Proof Of the Theorem And Its Corollariesmentioning
confidence: 82%
“…Hence, S + cannot be a Cowen-Douglas operator. When S * + is a Cowen-Douglas operator has been characterized in [5]. In this note, we will prove the following theorem.…”
Section: Introductionmentioning
confidence: 94%
“…In [5], σ e (S + ) and the indices associated with all holes in σ e (S + ) have been described. For convenience, we draw the following conclusions.…”
“…By the Riesz decomposition theorem, if σ(T ) is not connected, then T is not strongly irreducible. For a unilateral operator weighted shift S + , it follows from Theorem 3.1 in [5] that if σ e (S + ) is not connected, then S + is not strongly irreducible. For a bilateral operator weighted shift S, however, the following example shows that a similar claim is false even though S is a Cowen-Douglas operator.…”
Section: Corollary 1 Let S Be a Bilateral Scalar Weighted Shift Thementioning
“…In [4], Ben-Artzi and Gohberg introduced the concepts of Bohl exponent and canonical splitting projection to describe the spectrum and the essential spectrum of operator weighted shifts of finite multiplicity (see also [10]). However, in the general setting of bilateral operator weighted shifts of infinite multiplicity, the complete description of the spectrum and its parts is not yet settled.…”
Section: Conversely Suppose That P(s X) < N(s X) and Letmentioning
Abstract. In this paper, we give necessary and sufficient conditions for a bilateral operator weighted shift to enjoy the single-valued extension property.
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