1996
DOI: 10.1016/0012-365x(95)00207-d
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The Erdős-Sós conjecture for graphs of girth 5

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Cited by 52 publications
(37 citation statements)
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“…Our work sheds some light on why the Erdős-Sós conjecture, which we already discussed in the beginning of the introduction, becomes easier for graphs with no short cycles or no complete bipartite subgraphs K 2,r . These scenarios were considered, e.g., in [8,15,12,16]. In particular, assuming that graph G has girth 2k +1,k ≥ 2, and minimum degree d, Jiang [12] showed how to embed in G all trees with kd vertices and degrees bounded by d. Although this is best possible, our result implies that this statement can be tight only for relatively few very special trees, i.e., those that contain several large stars of degree extremely close to d. Indeed, if we relax the degree assumption and consider trees with maximum degree at most (1 − )d, then it is possible to embed trees of order O(d k ) rather than O(d).…”
Section: Discussionmentioning
confidence: 99%
See 1 more Smart Citation
“…Our work sheds some light on why the Erdős-Sós conjecture, which we already discussed in the beginning of the introduction, becomes easier for graphs with no short cycles or no complete bipartite subgraphs K 2,r . These scenarios were considered, e.g., in [8,15,12,16]. In particular, assuming that graph G has girth 2k +1,k ≥ 2, and minimum degree d, Jiang [12] showed how to embed in G all trees with kd vertices and degrees bounded by d. Although this is best possible, our result implies that this statement can be tight only for relatively few very special trees, i.e., those that contain several large stars of degree extremely close to d. Indeed, if we relax the degree assumption and consider trees with maximum degree at most (1 − )d, then it is possible to embed trees of order O(d k ) rather than O(d).…”
Section: Discussionmentioning
confidence: 99%
“…The conjecture has been proved in several special cases, e.g. Brandt and Dobson [8] establish it for graphs of girth at least 5 (the girth is the length of the shortest cycle in a graph). In fact, they prove a stronger statement, that any such graph of minimum degree d/2 and maximum degree Δ contains all trees with d edges and maximum degree at most Δ.…”
Section: Extremal Questionsmentioning
confidence: 99%
“…As remarked in [5], the condition that the average degree of the graph G is greater than k À 1 from the Erdo ÂÂs±So Âs conjecture is replaced in Loebl±Komlo Âs± So Âs conjecture by the condition that the medium degree of G is greater than k (for some special cases of the Erdo ÂÂs±So Âs conjecture see for example [8] as well as [2] and [7]). …”
Section: Conjecture 2 (Erdo ââS±so âS)mentioning
confidence: 98%
“…Their conjecture has attracted a fair amount of attention over the last decades. Partial solutions are given in , and in the early 1990s, Ajtai, Komlós, Simonovits, and Szemerédi announced a proof of this result for sufficiently large m. To see that the Erdős‐Sós conjecture is best possible, observe that no (m1)‐regular graph contains the star K1,m as a subgraph.…”
Section: Introductionmentioning
confidence: 99%