2008
DOI: 10.1007/s00222-008-0137-7
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The Effros–Ruan conjecture for bilinear forms on C*-algebras

Abstract: Abstract. In 1991 Effros and Ruan conjectured that a certain Grothendieck-type inequality for a bilinear form on C * -algebras holds if (and only if) the bilinear form is jointly completely bounded. In 2002Pisier and Shlyakhtenko proved that this inequality holds in the more general setting of operator spaces, provided that the operator spaces in question are exact. Moreover, they proved that the conjecture of Effros and Ruan holds for pairs of C * -algebras, of which at least one is exact. In this paper we pr… Show more

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Cited by 31 publications
(62 citation statements)
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“…where the second line follows from the normalization assumption Tr(P 2 ) = Tr(Id) = n on elements of S. Combining (34) and (35) gives (33), completing the second step of the proof.…”
Section: Moreover T Can Be Taken With Real Coefficientsmentioning
confidence: 76%
“…where the second line follows from the normalization assumption Tr(P 2 ) = Tr(Id) = n on elements of S. Combining (34) and (35) gives (33), completing the second step of the proof.…”
Section: Moreover T Can Be Taken With Real Coefficientsmentioning
confidence: 76%
“…In particular Grothendieck's fundamental work on tensor norms leads to many interesting new problems in the context of operator algebras and operator spaces. Let us mention in particular Shlyakhtenko and Pisier's version of Grothendieck's theorem for operator spaces, Haagerup and Musat's the very recent completion of Grothendieck's theorem for C * -algebras [4] and the results in [7,19,20]. A fundamental object in the theory of operator spaces is Pisier's operator space OH, the only operator space completely isometric to its anti-dual.…”
Section: Introductionmentioning
confidence: 98%
“…We also see in [8,Example 3.6], or in Example 6.5 below, that the bilinear ideals SMB and J CB do not coincide.…”
Section: Example 62 a Multiplicatively Bounded Bilinear Mapping Whimentioning
confidence: 88%