2013
DOI: 10.1002/rsa.20517
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The diamond‐free process

Abstract: denote the diamond graph, formed by removing an edge from the complete graph K 4 . We consider the following random graph process: starting with n isolated vertices, add edges uniformly at random provided no such edge creates a copy of K − 4 . We show that, with probability tending to 1 as n → ∞, the final size of the graph produced is ( log n · n 3/2 ). Our analysis also suggests that the graph produced after i edges are added resembles the uniform random graph, with the additional condition that the edges wh… Show more

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Cited by 14 publications
(17 citation statements)
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“…For this process Picollelli [20] shows that the number of steps is larger than the bound given by (2) by a logarithmic factor. Bennett [2] has recent results on the sum-free process.…”
Section: Introductionmentioning
confidence: 84%
See 2 more Smart Citations
“…For this process Picollelli [20] shows that the number of steps is larger than the bound given by (2) by a logarithmic factor. Bennett [2] has recent results on the sum-free process.…”
Section: Introductionmentioning
confidence: 84%
“…When H is a diamond then the hypergraph H is 5‐uniform and 5(n2)(n3)/2‐regular but has Δ3(H)=3(n3)=Θ(D1/2). For this process Picollelli shows that the number of steps is larger than the bound given by (2) by a logarithmic factor. Bennett has recent results on the sum‐free process.…”
Section: Introductionmentioning
confidence: 97%
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“…We believe that variants of Theorems 1 and 4 also hold for many other forbidden graphs (using semirandom variants of the H-free process [25,6,34,35,27]); we hope to return to this topic in a future work.…”
Section: Main Tool: Pseudo-random Triangle-free Subgraphsmentioning
confidence: 98%
“…where |X uv (i)| and |Z uv (i)| intuitively correspond to an 'open codegree' and the usual codegree, respectively (note that |Y uv (i)| corresponds to a 'mixed codegree', see (16)). Guided by Section 2.2, we define Ψ(x) as the unique solution to the differential equation Ψ ′ (x) = exp(−Ψ 2 (x)) and Ψ(0) = 0 from (27). With the heuristics (22) in mind, we introduce the parameters…”
Section: Definitions and Parametersmentioning
confidence: 99%