Abstract:Crystals of monobromodehydrobispulegone, C20H27BrO, are orthorhombic, space group P2~2121, with four molecules per unit cell. The lattice constants are: a = 11.656 (2), b = 11.669 (2), c = 12.766 (2)/~. The crystal structure has been solved by the heavy-atom technique and refined by the full-matrix least-squares method. The final R index for 692 independent observed reflexions is 0.107. The molecule shows stress in the pentagonal ring. In the cyclohexane ring the oxygen and bromine substituents appear to be co… Show more
The molecular structure of “bishydropulegone,” a reductive dimer of pulegone, was determined as (1R,3′aR,4R,6′R,7′aS)-7-′a-hydroxy-2′,2′,3′,3′,4,6′-hexamethylspiro[cyclohexane-1,1′-indan]-2-one by X-ray crystallographic analysis.
The molecular structure of “bishydropulegone,” a reductive dimer of pulegone, was determined as (1R,3′aR,4R,6′R,7′aS)-7-′a-hydroxy-2′,2′,3′,3′,4,6′-hexamethylspiro[cyclohexane-1,1′-indan]-2-one by X-ray crystallographic analysis.
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