2012
DOI: 10.4007/annals.2012.175.3.14
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The connective constant of the honeycomb lattice equals sqrt(2+sqrt 2)

Abstract: We provide the first mathematical proof that the connective constant of the hexagonal lattice is equal to 2 + √ 2. This value has been derived nonrigorously by B. Nienhuis in 1982, using Coulomb gas approach from theoretical physics. Our proof uses a parafermionic observable for the self-avoiding walk, which satisfies a half of the discrete Cauchy-Riemann relations. Establishing the other half of the relations (which conjecturally holds in the scaling limit) would also imply convergence of the self-avoiding wa… Show more

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Cited by 167 publications
(260 citation statements)
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“…The limit is known as SLE 6 , which has an independent definition (to be given below) that does not depend on the lattice. We remark that Smirnov's proof only applies to the hexagonal lattice, although it is widely believed that Theorem 1.0.1 holds for several other lattices, such as the square lattice.…”
mentioning
confidence: 99%
“…The limit is known as SLE 6 , which has an independent definition (to be given below) that does not depend on the lattice. We remark that Smirnov's proof only applies to the hexagonal lattice, although it is widely believed that Theorem 1.0.1 holds for several other lattices, such as the square lattice.…”
mentioning
confidence: 99%
“…Despite decades of efforts, these questions remain unsolved, especially in low dimensions. It has recently been shown [6] ≈ 2.64). For two-dimensional lattices, it is conjectured that γ = 43/32 and that, for the uniform distribution, ν = 3/4.…”
Section: Introductionmentioning
confidence: 88%
“…Despite decades of efforts, these questions remain unsolved, especially in low dimensions. It has recently been shown [6] that the connective constant for the hexagonal lattice on plane is 2 + √ 2. Conversely, for the square lattice on plane, it is conjectured [11] that the connective constant is the unique positive root of 13x…”
Section: Introductionmentioning
confidence: 99%
“…For example, if we take ℱ N to be the set of all SAWs, we can split a walk w ∈ ℱ N into a unique initial part of length m and a final part of length N − m , which establishes (2). In general, determining the value of the connective constant requires significant ingenuity (see, e.g., [10], which establishes the value for SAWs on the two-dimensional hexagonal lattice).…”
Section: Introductionmentioning
confidence: 99%