2017
DOI: 10.1016/j.disc.2016.08.005
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The complexity of signed graph and edge-coloured graph homomorphisms

Abstract: We study homomorphism problems of signed graphs from a computational point of view. A signed graph (G, Σ) is a graph G where each edge is given a sign, positive or negative; Σ ⊆ E(G) denotes the set of negative edges. Thus, (G, Σ) is a 2-edge-coloured graph with the property that the edge-colours, {+, −}, form a group under multiplication. Central to the study of signed graphs is the operation of switching at a vertex, that results in changing the sign of each incident edge. We study two types of homomorphisms… Show more

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Cited by 37 publications
(65 citation statements)
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“…Extending the Hell-Nešetřil dichotomy [27] for Hom(H) for 1-edge-coloured graph problems, a complexity dichotomy for s-Hom(H) problems was proved in the papers [7,10]. The authors showed that if the s-core of a signed graph H has at least three edges, then s-Hom(H) is NP-complete; it is polynomial-time otherwise.…”
Section: S-hom(h)mentioning
confidence: 99%
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“…Extending the Hell-Nešetřil dichotomy [27] for Hom(H) for 1-edge-coloured graph problems, a complexity dichotomy for s-Hom(H) problems was proved in the papers [7,10]. The authors showed that if the s-core of a signed graph H has at least three edges, then s-Hom(H) is NP-complete; it is polynomial-time otherwise.…”
Section: S-hom(h)mentioning
confidence: 99%
“…An interesting case is the one when H = (C k , σ) is a cycle (k ≥ 3). If H is switching-equivalent either to an all-positive C k , or to an all-negative C k , then the complexity of s-Hom(H) and Planar s-Hom(H) are the same as the ones of Hom(C k ) and Planar Hom(C k ), respectively [7]. When k is odd, one of these two cases holds, and thus by the results of [25,33], in that case Planar s-Hom(H) is NP-complete.…”
Section: Planar S-hom(h)mentioning
confidence: 99%
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