“…3 by [14, Theorem 1]. Therefore each GL 2 (Z)-equivalence class of F is associated to ≪ (N/g) 2 3 integral points. Observe that a, h, u, g 0 , g 1 together determines the GL 2 (Z)-equivalence class of F , and g 0 is determined by a, h, u, g 1 by (5.2).…”